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1951 AMC 12 真题(P版)

数学 1951 年 50 题 61 KB 含答案解析

中英双语:每题先中文,后附英文原题;解答在同页下方「查看答案解析与下载」里。

1

\(M\) 比 \(N\) 大的百分率为:

A\(\dfrac{100(M-N)}{M}\) B\(\dfrac{100(M-N)}{N}\) C\(\dfrac{M-N}{N}\) D\(\dfrac{M-N}{M}\) E\(\dfrac{100(M+N)}{N}\)

English

The percent that \(M\) is greater than \(N\) is:

(A) \(\dfrac{100(M-N)}{M}\)(B) \(\dfrac{100(M-N)}{N}\)(C) \(\dfrac{M-N}{N}\)(D) \(\dfrac{M-N}{M}\)(E) \(\dfrac{100(M+N)}{N}\)

2

一块长方形田地的宽是长的一半,四周共用 \(x\) 码栅栏围住。用 \(x\) 表示其面积为:

A\(\dfrac{x^2}{2}\) B\(2x^2\) C\(\dfrac{2x^2}{9}\) D\(\dfrac{x^2}{18}\) E\(\dfrac{x^2}{72}\)

English

A rectangular field is half as wide as it is long and is completely enclosed by \(x\) yards of fencing. The area in terms of \(x\) is:

(A) \(\dfrac{x^2}{2}\)(B) \(2x^2\)(C) \(\dfrac{2x^2}{9}\)(D) \(\dfrac{x^2}{18}\)(E) \(\dfrac{x^2}{72}\)

3

若正方形的对角线长为 \(a+b\),则正方形的面积为:

A\((a+b)^2\) B\(\dfrac12(a+b)^2\) C\(a^2+b^2\) D\(\dfrac12(a^2+b^2)\) E以上答案均不正确

English

If the length of a diagonal of a square is \(a+b,\) then the area of the square is:

(A) \((a+b)^2\)(B) \(\dfrac12(a+b)^2\)(C) \(a^2+b^2\)(D) \(\dfrac12(a^2+b^2)\)(E) None of these

4

一座平顶长方体谷仓宽 \(10\) 码、长 \(13\) 码、高 \(5\) 码。谷仓内外墙面和天花板都要粉刷,但屋顶和地面不刷。需要粉刷的总面积为多少平方码?

A\(360\) B\(460\) C\(490\) D\(590\) E\(720\)

English

A barn with a flat roof is rectangular in shape, \(10\) yd. wide, \(13\) yd. long, and \(5\) yd. high. It is to be painted inside and outside, and on the ceiling, but not on the roof or floor. The total number of square yards to be painted is:

(A) \(360\)(B) \(460\)(C) \(490\)(D) \(590\)(E) \(720\)

5

\(A\) 先生拥有一栋价值 \(\$10{,}000\) 的房子。他以高于房屋价值 \(10\%\) 的价格卖给 \(B\) 先生。随后,\(B\) 先生以亏损 \(10\%\) 的价格将房子卖回给 \(A\) 先生。则:

A\(A\) 收支相抵 B\(A\) 在交易中赚了 \(\$1100\) C\(A\) 在交易中赚了 \(\$1000\) D\(A\) 在交易中亏了 \(\$900\) E\(A\) 在交易中亏了 \(\$1000\)

English

Mr. \(A\) owns a home worth \(\$10{,}000.\) He sells it to Mr. \(B\) at a \(10\%\) profit based on the worth of the house. Mr. \(B\) sells the house back to Mr. \(A\) at a \(10\%\) loss. Then:

(A) \(A\) comes out even(B) \(A\) makes \(\$1100\) on the deal(C) \(A\) makes \(\$1000\) on the deal(D) \(A\) loses \(\$900\) on the deal(E) \(A\) loses \(\$1000\) on the deal

6

已知一个长方体盒子的底面、侧面和正面面积。这三个面积的乘积等于:

A盒子的体积 B体积的平方根 C体积的两倍 D体积的平方 E体积的立方

English

The bottom, side, and front areas of a rectangular box are known. The product of these areas is equal to:

(A) The volume of the box(B) The square root of the volume(C) Twice the volume(D) The square of the volume(E) The cube of the volume

7

测量一条长 \(10''\) 的线段时误差为 \(0.02''\),而测量一条长 \(100''\) 的线段时误差仅为 \(0.2''\)。与第一次测量的相对误差相比,第二次测量的相对误差:

A大 \(0.18\) B相同 C较小 D是其 \(10\) 倍 E\((A)\) 和 \((D)\) 的描述都正确

English

An error of \(0.02''\) is made in the measurement of a line \(10''\) long, while an error of only \(0.2''\) is made in a measurement of a line \(100''\) long. In comparison with the relative error of the first measurement, the relative error of the second measurement is:

(A) Greater by \(0.18\)(B) The same(C) Less(D) \(10\) times as great(E) Correctly described by both \((A)\) and \((D)\)

8

一件商品的价格降低了 \(10\%\)。要恢复原价,降价后的价格必须增加:

A\(10\%\) B\(9\%\) C\(11\dfrac19\%\) D\(11\%\) E以上答案均不正确

English

The price of an article is cut \(10\%.\) To restore it to its former value, the new price must be increased by:

(A) \(10\%\)(B) \(9\%\)(C) \(11\dfrac19\%\)(D) \(11\%\)(E) None of these answers

9

先画一个边长为 \(a\) 的等边三角形,再连接其三边中点,得到一个新的等边三角形;随后连接第二个三角形的三边中点,得到第三个等边三角形;如此无限继续。所有这些三角形周长之和的极限为:

A无穷大 B\(\left(5\dfrac14\right)a\) C\(2a\) D\(6a\) E\(\left(4\dfrac12\right)a\)

English

An equilateral triangle is drawn with a side of length \(a.\) A new equilateral triangle is formed by joining the midpoints of the sides of the first one. Then a third equilateral triangle is formed by joining the midpoints of the sides of the second; and so on forever. The limit of the sum of the perimeters of all the triangles thus drawn is:

(A) Infinite(B) \(\left(5\dfrac14\right)a\)(C) \(2a\)(D) \(6a\)(E) \(\left(4\dfrac12\right)a\)

10

下列说法中,不正确的是:

A将一个给定长方形的底边加倍,面积也加倍。 B将三角形的高加倍,面积也加倍。 C将一个给定圆的半径加倍,面积也加倍。 D将一个分式的除数加倍,并将其分子除以 \(2\),会改变商。 E将一个给定的量加倍,可能使结果小于原来的量。

English

Of the following statements, the one that is incorrect is:

(A) Doubling the base of a given rectangle doubles the area.(B) Doubling the altitude of a triangle doubles the area.(C) Doubling the radius of a given circle doubles the area.(D) Doubling the divisor of a fraction and dividing its numerator by \(2\) changes the quotient.(E) Doubling a given quantity may make it less than it originally was.

11

一个无穷等比数列的和为 \(\dfrac{a}{1-r}\),其中 \(a\) 表示首项,\(-1\lt r\lt1\) 表示公比。该数列各项平方之和为:

A\(\dfrac{a^2}{(1-r)^2}\) B\(\dfrac{a^2}{1+r^2}\) C\(\dfrac{a^2}{1-r^2}\) D\(\dfrac{4a^2}{1+r^2}\) E以上答案均不正确

English

The limit of the sum of an infinite number of terms in a geometric progression is \(\dfrac{a}{1-r},\) where \(a\) denotes the first term and \(-1\lt r\lt1\) denotes the common ratio. The limit of the sum of their squares is:

(A) \(\dfrac{a^2}{(1-r)^2}\)(B) \(\dfrac{a^2}{1+r^2}\)(C) \(\dfrac{a^2}{1-r^2}\)(D) \(\dfrac{4a^2}{1+r^2}\)(E) None of these

12

在 \(2{:}15\) 时,钟表的时针与分针所成的角为:

A\(30^\circ\) B\(5^\circ\) C\(22\dfrac12^\circ\) D\(7\dfrac12^\circ\) E\(28^\circ\)

English

At \(2{:}15\) o’clock, the hour and minute hands of a clock form an angle of:

(A) \(30^\circ\)(B) \(5^\circ\)(C) \(22\dfrac12^\circ\)(D) \(7\dfrac12^\circ\)(E) \(28^\circ\)

13

\(A\) 可在 \(9\) 天内完成一项工作。\(B\) 的效率比 \(A\) 高 \(50\%\)。\(B\) 完成同一项工作所需的天数为:

A\(13\dfrac12\) B\(4\dfrac12\) C\(6\) D\(3\) E以上答案均不正确

English

\(A\) can do a piece of work in \(9\) days. \(B\) is \(50\%\) more efficient than \(A.\) The number of days it takes \(B\) to do the same piece of work is:

(A) \(13\dfrac12\)(B) \(4\dfrac12\)(C) \(6\)(D) \(3\)(E) None of these answers

14

关于几何证明,请指出下列哪一项说法不正确:

A有些陈述无需证明即可接受。 B在某些情况下,证明某些命题时存在不止一种正确的步骤顺序。 C证明中使用的每一个术语都必须事先定义。 D如果已知条件中含有一个不真实的命题,就不可能通过正确推理得出真实的结论。 E只要存在两个或更多互相矛盾的命题,就可以使用间接证明。

English

In connection with proof in geometry, indicate which one of the following statements is incorrect:

(A) Some statements are accepted without being proved.(B) In some instances there is more than one correct order in proving certain propositions.(C) Every term used in a proof must have been defined previously.(D) It is not possible to arrive by correct reasoning at a true conclusion if, in the given, there is an untrue proposition.(E) Indirect proof can be used whenever there are two or more contrary propositions.

15

对于 \(n\) 的一切整数值,表达式 \(n^3-n\) 恒能被下列哪个最大的数整除?

A\(2\) B\(3\) C\(4\) D\(5\) E\(6\)

English

The largest number by which the expression \(n^3-n\) is divisible for all possible integral values of \(n\) is:

(A) \(2\)(B) \(3\)(C) \(4\)(D) \(5\)(E) \(6\)

16

对二次方程 \[ f(x)=ax^2+bx+c=0 \] 使用求根公式时,若恰有 \(c=\dfrac{b^2}{4a}\),则 \(y=f(x)\) 的图像一定:

A有最大值 B有最小值 C与 \(x\) 轴相切 D与 \(y\) 轴相切 E只位于一个象限内

English

If in applying the quadratic formula to a quadratic equation \[ f(x)=ax^2+bx+c=0, \] it happens that \(c=\dfrac{b^2}{4a},\) then the graph of \(y=f(x)\) will certainly:

(A) Have a maximum(B) Have a minimum(C) Be tangent to the \(x\)-axis(D) Be tangent to the \(y\)-axis(E) Lie in one quadrant only

17

请指出下列哪个方程中,\(y\) 与 \(x\) 既不成正比,也不成反比:

A\(x+y=0\) B\(3xy=10\) C\(x=5y\) D\(3x+y=10\) E\(\dfrac{x}{y}=\sqrt3\)

English

Indicate in which one of the following equations \(y\) is neither directly nor inversely proportional to \(x\):

(A) \(x+y=0\)(B) \(3xy=10\)(C) \(x=5y\)(D) \(3x+y=10\)(E) \(\dfrac{x}{y}=\sqrt3\)

18

要将表达式 \(21x^2+ax+21\) 分解为两个系数为整数的线性不可约二项式之积。当 \(a\) 是下列哪一项时,可以完成这种分解?

A任意奇数 B某些奇数 C任意偶数 D某些偶数 E零

English

The expression \(21x^2+ax+21\) is to be factored into two linear prime binomial factors with integer coefficients. This can be done if \(a\) is:

(A) Any odd number(B) Some odd number(C) Any even number(D) Some even number(E) Zero

19

将一个三位数重复书写一次,组成一个六位数,例如 \(256{,}256\)、\(678{,}678\) 等。任何这种形式的数都一定能被下列哪个数整除?

A仅 \(7\) B仅 \(11\) C仅 \(13\) D\(101\) E\(1001\)

English

A six-place number is formed by repeating a three-place number; for example, \(256{,}256,\) or \(678{,}678,\) etc. Any number of this form is always exactly divisible by:

(A) \(7\) only(B) \(11\) only(C) \(13\) only(D) \(101\)(E) \(1001\)

20

将表达式 \((x+y)^{-1}(x^{-1}+y^{-1})\) 化简,并用负指数表示,结果等于:

A\(x^{-2}+2x^{-1}y^{-1}+y^{-2}\) B\(x^{-2}+2^{-1}x^{-1}y^{-1}+y^{-2}\) C\(x^{-1}y^{-1}\) D\(x^{-2}+y^{-2}\) E\(\dfrac{1}{x^{-1}y^{-1}}\)

English

When simplified and expressed with negative exponents, the expression \((x+y)^{-1}(x^{-1}+y^{-1})\) is equal to:

(A) \(x^{-2}+2x^{-1}y^{-1}+y^{-2}\)(B) \(x^{-2}+2^{-1}x^{-1}y^{-1}+y^{-2}\)(C) \(x^{-1}y^{-1}\)(D) \(x^{-2}+y^{-2}\)(E) \(\dfrac{1}{x^{-1}y^{-1}}\)

21

已知 \(x\gt0\)、\(y\gt0\)、\(x\gt y\),且 \(z\ne0\)。下列不等式中,不一定正确的是:

A\(x+z\gt y+z\) B\(x-z\gt y-z\) C\(xz\gt yz\) D\(\dfrac{x}{z^2}\gt\dfrac{y}{z^2}\) E\(xz^2\gt yz^2\)

English

Given \(x\gt0,\) \(y\gt0,\) \(x\gt y,\) and \(z\ne0.\) The inequality which is not always correct is:

(A) \(x+z\gt y+z\)(B) \(x-z\gt y-z\)(C) \(xz\gt yz\)(D) \(\dfrac{x}{z^2}\gt\dfrac{y}{z^2}\)(E) \(xz^2\gt yz^2\)

22

方程 \(\log_{10}(a^2-15a)=2\) 中 \(a\) 的值为:

A\(\dfrac{15\pm\sqrt{233}}{2}\) B\(20\)、\(-5\) C\(\dfrac{15\pm\sqrt{305}}{2}\) D\(\pm20\) E以上答案均不正确

English

The values of \(a\) in the equation \(\log_{10}(a^2-15a)=2\) are:

(A) \(\dfrac{15\pm\sqrt{233}}{2}\)(B) \(20,\) \(-5\)(C) \(\dfrac{15\pm\sqrt{305}}{2}\)(D) \(\pm20\)(E) None of these

23

一个圆柱形盒子的半径为 \(8\) 英寸,高为 \(3\) 英寸。分别给半径或高增加相同的长度,若要使两种情况下体积的非零增量相等,则应增加多少英寸?

A\(1\) B\(5\dfrac13\) C任意数 D不存在 E以上答案均不正确

English

The radius of a cylindrical box is \(8\) inches and the height is \(3\) inches. The number of inches that may be added to either the radius or the height to give the same nonzero increase in volume is:

(A) \(1\)(B) \(5\dfrac13\)(C) Any number(D) Non-existent(E) None of these

24

化简 \(\dfrac{2^{n+4}-2(2^n)}{2(2^{n+3})}\),结果为:

A\(2^{n+1}-\dfrac18\) B\(-2^{n+1}\) C\(1-2^n\) D\(\dfrac78\) E\(\dfrac74\)

English

When simplified, \(\dfrac{2^{n+4}-2(2^n)}{2(2^{n+3})}\) is:

(A) \(2^{n+1}-\dfrac18\)(B) \(-2^{n+1}\)(C) \(1-2^n\)(D) \(\dfrac78\)(E) \(\dfrac74\)

25

一个正方形的面积数值等于其周长数值;一个等边三角形的面积数值也等于其周长数值。比较它们的边心距,前者的边心距:

A等于后者 B是后者的 \(\dfrac43\) 倍 C是后者的 \(\dfrac{2}{\sqrt3}\) 倍 D是后者的 \(\dfrac{\sqrt2}{\sqrt3}\) 倍 E与后者的关系无法确定

English

The apothem of a square having its area numerically equal to its perimeter is compared with the apothem of an equilateral triangle having its area numerically equal to its perimeter. The first apothem will be:

(A) Equal to the second(B) \(\dfrac43\) times the second(C) \(\dfrac{2}{\sqrt3}\) times the second(D) \(\dfrac{\sqrt2}{\sqrt3}\) times the second(E) Indeterminately related to the second

26

在方程 \[ \frac{x(x-1)-(m+1)}{(x-1)(m-1)}=\frac{x}{m} \] 中,当下列哪一条件成立时,两根相等?

A\(m=1\) B\(m=\dfrac12\) C\(m=0\) D\(m=-1\) E\(m=-\dfrac12\)

English

In the equation \[ \frac{x(x-1)-(m+1)}{(x-1)(m-1)}=\frac{x}{m}, \] the roots are equal when:

(A) \(m=1\)(B) \(m=\dfrac12\)(C) \(m=0\)(D) \(m=-1\)(E) \(m=-\dfrac12\)

27

过三角形内一点,从三个顶点分别向对边画直线,将原三角形分成六个三角形区域。则:

A每一对相对的三角形都相似 B每一对相对的三角形都全等 C每一对相对的三角形面积都相等 D形成三个相似的四边形 E以上关系均不成立

English

Through a point inside a triangle, three lines are drawn from the vertices to the opposite sides, forming six triangular sections. Then:

(A) The triangles are similar in opposite pairs(B) The triangles are congruent in opposite pairs(C) The triangles are equal in area in opposite pairs(D) Three similar quadrilaterals are formed(E) None of the above relations is true

28

风对帆的压力 \(P\) 与帆的面积 \(A\) 及风速 \(V\) 的平方成联合正比。当风速为每小时 \(16\) 英里时,每平方英尺帆面所受压力为 \(1\) 磅。当一平方码帆面所受压力为 \(36\) 磅时,风速为:

A\(10\dfrac23\) 英里/小时 B\(96\) 英里/小时 C\(32\) 英里/小时 D\(1\dfrac13\) 英里/小时 E\(16\) 英里/小时

English

The pressure \(P\) of wind on a sail varies jointly as the area \(A\) of the sail and the square of the velocity \(V\) of the wind. The pressure on a square foot is \(1\) pound when the velocity is \(16\) miles per hour. The velocity of the wind when the pressure on a square yard is \(36\) pounds is:

(A) \(10\dfrac23\) mph(B) \(96\) mph(C) \(32\) mph(D) \(1\dfrac13\) mph(E) \(16\) mph

29

下列各组数据中,唯一不能确定三角形形状的是:

A两边之比及其夹角 B三条高之比 C三条中线之比 D一条高与其对应底边之比 E两个角

English

Of the following sets of data, the only one that does not determine the shape of a triangle is:

(A) The ratio of two sides and the included angle(B) The ratios of the three altitudes(C) The ratios of the three medians(D) The ratio of the altitude to the corresponding base(E) Two angles

30

两根高分别为 \(20''\) 和 \(80''\) 的杆相距 \(100''\)。分别连接每根杆的顶端与另一根杆的底端,则两条连线交点的高度为:

A\(50''\) B\(40''\) C\(16''\) D\(60''\) E以上答案均不正确

English

If two poles \(20''\) and \(80''\) high are \(100''\) apart, then the height of the intersection of the lines joining the top of each pole to the foot of the opposite pole is:

(A) \(50''\)(B) \(40''\)(C) \(16''\)(D) \(60''\)(E) None of these

31

一次聚会结束时,人们共握手 \(28\) 次。假设每位参加者对其他所有人都同样礼貌,则在场人数为:

A\(14\) B\(28\) C\(56\) D\(8\) E\(7\)

English

A total of \(28\) handshakes was exchanged at the conclusion of a party. Assuming that each participant was equally polite toward all the others, the number of people present was:

(A) \(14\)(B) \(28\)(C) \(56\)(D) \(8\)(E) \(7\)

32

若 \(\triangle ABC\) 内接于以 \(\overline{AB}\) 为直径的半圆,则 \(\overline{AC}+\overline{BC}\) 必须:

A等于 \(\overline{AB}\) B等于 \(\overline{AB}\sqrt2\) C\(\ge \overline{AB}\sqrt2\) D\(\le \overline{AB}\sqrt2\) E\(\overline{AB}^{\,2}\)

English

If \(\triangle ABC\) is inscribed in a semicircle whose diameter is \(\overline{AB},\) then \(\overline{AC}+\overline{BC}\) must be:

(A) Equal to \(\overline{AB}\)(B) Equal to \(\overline{AB}\sqrt2\)(C) \(\ge \overline{AB}\sqrt2\)(D) \(\le \overline{AB}\sqrt2\)(E) \(\overline{AB}^{\,2}\)

33

下列每一对方程的图像交点横坐标都可以给出方程 \(x^2-2x=0\) 的根,唯独哪一对不能?

A\(y=x^2\),\(y=2x\) B\(y=x^2-2x\),\(y=0\) C\(y=x\),\(y=x-2\) D\(y=x^2-2x+1\),\(y=1\) E\(y=x^2-1\),\(y=2x-1\)

English

The roots of the equation \(x^2-2x=0\) can be obtained graphically by finding the abscissas of the points of intersection of each of the following pairs of equations except the pair:

(A) \(y=x^2,\) \(y=2x\)(B) \(y=x^2-2x,\) \(y=0\)(C) \(y=x,\) \(y=x-2\)(D) \(y=x^2-2x+1,\) \(y=1\)(E) \(y=x^2-1,\) \(y=2x-1\)

34

\(10^{\log_{10}7}\) 的值为:

A\(7\) B\(1\) C\(10\) D\(\log_{10}7\) E\(\log_7 10\)

English

The value of \(10^{\log_{10}7}\) is:

(A) \(7\)(B) \(1\)(C) \(10\)(D) \(\log_{10}7\)(E) \(\log_7 10\)

35

若 \(a^x=c^q=b\),且 \(c^y=a^z=d\),则:

A\(xy=qz\) B\(\dfrac{x}{y}=\dfrac{q}{z}\) C\(x+y=q+z\) D\(x-y=q-z\) E\(x^y=q^z\)

English

If \(a^x=c^q=b\) and \(c^y=a^z=d,\) then:

(A) \(xy=qz\)(B) \(\dfrac{x}{y}=\dfrac{q}{z}\)(C) \(x+y=q+z\)(D) \(x-y=q-z\)(E) \(x^y=q^z\)

36

下列用于证明一个几何图形是轨迹的方法中,哪一种不正确?

A轨迹上的每一点都满足条件,轨迹外的每一点都不满足条件。 B每个不满足条件的点都不在轨迹上,且轨迹上的每一点都满足条件。 C每个满足条件的点都在轨迹上,且轨迹上的每一点都满足条件。 D轨迹外的每一点都不满足条件,且每个不满足条件的点都不在轨迹上。 E每个满足条件的点都在轨迹上,且每个不满足条件的点都不在轨迹上。

English

Which of the following methods of proving a geometric figure a locus is not correct?

(A) Every point on the locus satisfies the conditions and every point not on the locus does not satisfy the conditions.(B) Every point not satisfying the conditions is not on the locus and every point on the locus does satisfy the conditions.(C) Every point satisfying the conditions is on the locus and every point on the locus satisfies the conditions.(D) Every point not on the locus does not satisfy the conditions and every point not satisfying the conditions is not on the locus.(E) Every point satisfying the conditions is on the locus and every point not satisfying the conditions is not on the locus.

37

有一个数,除以 \(10\) 余 \(9\),除以 \(9\) 余 \(8\),除以 \(8\) 余 \(7\),依此类推,直到除以 \(2\) 余 \(1\)。这个数是:

A\(59\) B\(419\) C\(1259\) D\(2519\) E以上答案均不正确

English

A number which when divided by \(10\) leaves a remainder of \(9,\) when divided by \(9\) leaves a remainder of \(8,\) by \(8\) leaves a remainder of \(7,\) etc., down to where, when divided by \(2,\) it leaves a remainder of \(1,\) is:

(A) \(59\)(B) \(419\)(C) \(1259\)(D) \(2519\)(E) None of these answers

38

一条铁路要越过一座山,需要上升 \(600\) 英尺。延长轨道并使其绕过山峰,可以降低坡度。要将坡度从 \(3\%\) 降至 \(2\%\),大约需要增加多长的轨道?

A\(10{,}000\) 英尺 B\(20{,}000\) 英尺 C\(30{,}000\) 英尺 D\(12{,}000\) 英尺 E以上答案均不正确

English

A rise of \(600\) feet is required to get a railroad line over a mountain. The grade can be kept down by lengthening the track and curving it around the mountain peak. The additional length of track required to reduce the grade from \(3\%\) to \(2\%\) is approximately:

(A) \(10{,}000\) ft.(B) \(20{,}000\) ft.(C) \(30{,}000\) ft.(D) \(12{,}000\) ft.(E) None of these

39

将一块石头投入井中,在投下后 \(7.7\) 秒听到石头撞击井底的声音。假设石头在 \(t\) 秒内下落 \(16t^2\) 英尺,声速为每秒 \(1120\) 英尺。井深为:

A\(784\) 英尺 B\(342\) 英尺 C\(1568\) 英尺 D\(156.8\) 英尺 E以上答案均不正确

English

A stone is dropped into a well and the report of the stone striking the bottom is heard \(7.7\) seconds after it is dropped. Assume that the stone falls \(16t^2\) feet in \(t\) seconds and that the velocity of sound is \(1120\) feet per second. The depth of the well is:

(A) \(784\) ft.(B) \(342\) ft.(C) \(1568\) ft.(D) \(156.8\) ft.(E) None of these

40

表达式 \[ \begin{aligned} &\left(\frac{(x+1)^2(x^2-x+1)^2}{(x^3+1)^2}\right)^2\\ &\quad{}\cdot \left(\frac{(x-1)^2(x^2+x+1)^2}{(x^3-1)^2}\right)^2 \end{aligned} \] 等于:

A\((x+1)^4\) B\((x^3+1)^4\) C\(1\) D\(\big[(x^3+1)(x^3-1)\big]^2\) E\(\big[(x^3-1)^2\big]^2\)

English

The expression \[ \begin{aligned} &\left(\frac{(x+1)^2(x^2-x+1)^2}{(x^3+1)^2}\right)^2\\ &\quad{}\cdot \left(\frac{(x-1)^2(x^2+x+1)^2}{(x^3-1)^2}\right)^2 \end{aligned} \] equals:

(A) \((x+1)^4\)(B) \((x^3+1)^4\)(C) \(1\)(D) \(\big[(x^3+1)(x^3-1)\big]^2\)(E) \(\big[(x^3-1)^2\big]^2\)

41

表中 \(x\) 与 \(y\) 之间的关系可用下列哪个公式表示?

\(x\) \(2\) \(3\) \(4\) \(5\) \(6\)
\(y\) \(0\) \(2\) \(6\) \(12\) \(20\)

A\(y=2x-4\) B\(y=x^2-3x+2\) C\(y=x^3-3x^2+2x\) D\(y=x^2-4x\) E\(y=x^2-4\)

English

The formula expressing the relationship between \(x\) and \(y\) in the table is:

\(x\) \(2\) \(3\) \(4\) \(5\) \(6\)
\(y\) \(0\) \(2\) \(6\) \(12\) \(20\)

(A) \(y=2x-4\)(B) \(y=x^2-3x+2\)(C) \(y=x^3-3x^2+2x\)(D) \(y=x^2-4x\)(E) \(y=x^2-4\)

42

若 \(x\) 等于 \[ \sqrt{1+\sqrt{1+\sqrt{1+\sqrt{1+\cdots}}}}\text{,}\] 则:

A\(x=1\) B\(0\lt x\lt1\) C\(1\lt x\lt2\) D\(x\) 是无穷大 E\(x\gt2\),但为有限值

English

If \(x\) equals \[ \sqrt{1+\sqrt{1+\sqrt{1+\sqrt{1+\cdots}}}}, \] then:

(A) \(x=1\)(B) \(0\lt x\lt1\)(C) \(1\lt x\lt2\)(D) \(x\) is infinite(E) \(x\gt2\) but finite

43

下列说法中,唯一不正确的是:

A不等式两边同时增加、减少、乘以或除以(除数不为零)同一个正数后,不等式仍然成立。 B两个不相等正数的算术平均数大于其几何平均数。 C两个正数的和一定时,二者相等时乘积最大。 D若 \(a\) 和 \(b\) 是不相等的正数,则 \(\dfrac12(a^2+b^2)\) 大于 \(\left[\dfrac12(a+b)\right]^2\)。 E两个正数的乘积一定时,二者相等时和最大。

English

Of the following statements, the only one that is incorrect is:

(A) An inequality will remain true after each side is increased, decreased, multiplied, or divided (zero excluded) by the same positive quantity.(B) The arithmetic mean of two unequal positive quantities is greater than their geometric mean.(C) If the sum of two positive quantities is given, their product is largest when they are equal.(D) If \(a\) and \(b\) are positive and unequal, \(\dfrac12(a^2+b^2)\) is greater than \(\left[\dfrac12(a+b)\right]^2.\)(E) If the product of two positive quantities is given, their sum is greatest when they are equal.

44

若 \(\dfrac{xy}{x+y}=a\)、\(\dfrac{xz}{x+z}=b\)、\(\dfrac{yz}{y+z}=c\),其中 \(a\)、\(b\)、\(c\) 均不为零,则 \(x\) 等于:

A\(\dfrac{abc}{ab+ac+bc}\) B\(\dfrac{2abc}{ab+bc+ac}\) C\(\dfrac{2abc}{ab+ac-bc}\) D\(\dfrac{2abc}{ab+bc-ac}\) E\(\dfrac{2abc}{ac+bc-ab}\)

English

If \(\dfrac{xy}{x+y}=a,\) \(\dfrac{xz}{x+z}=b,\) and \(\dfrac{yz}{y+z}=c,\) where \(a,\) \(b,\) \(c\) are other than zero, then \(x\) equals:

(A) \(\dfrac{abc}{ab+ac+bc}\)(B) \(\dfrac{2abc}{ab+bc+ac}\)(C) \(\dfrac{2abc}{ab+ac-bc}\)(D) \(\dfrac{2abc}{ab+bc-ac}\)(E) \(\dfrac{2abc}{ac+bc-ab}\)

45

已知 \(\log 8=0.9031\) 和 \(\log 9=0.9542\),则下列唯一不能在不查表的情况下求出的对数是:

A\(\log 17\) B\(\log(\frac{5}{4})\) C\(\log 15\) D\(\log 600\) E\(\log 0.4\)

English

If you are given \(\log 8=0.9031\) and \(\log 9=0.9542,\) then the only logarithm that cannot be found without the use of tables is:

(A) \(\log 17\)(B) \(\log(\frac{5}{4})\)(C) \(\log 15\)(D) \(\log 600\)(E) \(\log 0.4\)

46

\(\overline{AB}\) 是圆心为 \(O\) 的圆的一条固定直径。从圆上任意一点 \(C\) 作弦 \(\overline{CD}\),使其垂直于 \(\overline{AB}\)。当 \(C\) 在一个半圆上移动时,角 \(OCD\) 的平分线与圆相交于一点,该点始终:

A平分弧 \(AB\) B三等分弧 \(AB\) C位置随之变化 D到 \(\overline{AB}\) 的距离与到 \(D\) 的距离相等 E到 \(B\) 与 \(C\) 的距离相等

English

\(\overline{AB}\) is a fixed diameter of a circle whose center is \(O.\) From \(C,\) any point on the circle, a chord \(\overline{CD}\) is drawn perpendicular to \(\overline{AB}.\) Then, as \(C\) moves over a semicircle, the bisector of angle \(OCD\) cuts the circle in a point that always:

(A) Bisects the arc \(AB\)(B) Trisects the arc \(AB\)(C) Varies(D) Is as far from \(\overline{AB}\) as from \(D\)(E) Is equidistant from \(B\) and \(C\)

47

若 \(r\) 和 \(s\) 是方程 \(ax^2+bx+c=0\) 的根,则 \(\dfrac1{r^2}+\dfrac1{s^2}\) 的值为:

A\(b^2-4ac\) B\(\dfrac{b^2-4ac}{2a}\) C\(\dfrac{b^2-4ac}{c^2}\) D\(\dfrac{b^2-2ac}{c^2}\) E以上答案均不正确

English

If \(r\) and \(s\) are the roots of the equation \(ax^2+bx+c=0,\) the value of \(\dfrac1{r^2}+\dfrac1{s^2}\) is:

(A) \(b^2-4ac\)(B) \(\dfrac{b^2-4ac}{2a}\)(C) \(\dfrac{b^2-4ac}{c^2}\)(D) \(\dfrac{b^2-2ac}{c^2}\)(E) None of these

48

内接于半圆的正方形面积与内接于整圆的正方形面积之比为:

A\(1:2\) B\(2:3\) C\(2:5\) D\(3:4\) E\(3:5\)

English

The area of a square inscribed in a semicircle is to the area of the square inscribed in the entire circle as:

(A) \(1:2\)(B) \(2:3\)(C) \(2:5\)(D) \(3:4\)(E) \(3:5\)

49

从一个直角三角形的两个锐角顶点所作的中线长分别为 \(5\) 和 \(\sqrt{40}\)。斜边长为:

A\(10\) B\(2\sqrt{40}\) C\(\sqrt{13}\) D\(2\sqrt{13}\) E以上答案均不正确

English

The medians of a right triangle which are drawn from the vertices of the acute angles are \(5\) and \(\sqrt{40}.\) The value of the hypotenuse is:

(A) \(10\)(B) \(2\sqrt{40}\)(C) \(\sqrt{13}\)(D) \(2\sqrt{13}\)(E) None of these

50

汤姆、迪克和哈里一起开始一段 \(100\) 英里的旅程。汤姆与哈里乘汽车,以每小时 \(25\) 英里的速度前进;迪克则以每小时 \(5\) 英里的速度步行。行驶一段距离后,哈里下车,改以每小时 \(5\) 英里的速度继续步行;汤姆掉头去接迪克,并使迪克与哈里同时到达终点。整个旅程所需的小时数为:

A\(5\) B\(6\) C\(7\) D\(8\) E以上答案均不正确

English

Tom, Dick, and Harry started out on a \(100\)-mile journey. Tom and Harry went by automobile at the rate of \(25\) mph, while Dick walked at the rate of \(5\) mph. After a certain distance, Harry got off and walked on at \(5\) mph, while Tom went back for Dick and got him to the destination at the same time that Harry arrived. The number of hours required for the trip was:

(A) \(5\)(B) \(6\)(C) \(7\)(D) \(8\)(E) None of these answers

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逐题解析

1 答案 B

从 \(N\) 增加到 \(M\) 的增加量为 \(M-N\)。除以原数量并乘以 \(100\),得到 \[ \frac{100(M-N)}{N}\text{。}\]

因此,正确答案是 B。

English

The increase from \(N\) to \(M\) is \(M-N.\) Dividing by the original quantity and multiplying by \(100\) gives \[ \frac{100(M-N)}{N}. \]

Thus, the correct answer is B.

2 答案 D

设宽为 \(w\),则长为 \(2w\)。由栅栏总长可得 \(2(w+2w)=6w=x\),所以 \(w=\frac{x}{6}\)。因此, \[ A=w(2w)=2\left(\frac{x}{6}\right)^2=\frac{x^2}{18}\text{。}\]

因此,正确答案是 D。

English

Let the width be \(w\), so the length is \(2w.\) The fencing gives \(2(w+2w)=6w=x,\) hence \(w=\frac{x}{6}.\) Therefore \[ A=w(2w)=2\left(\frac{x}{6}\right)^2=\frac{x^2}{18}. \]

Thus, the correct answer is D.

3 答案 B

若边长为 \(s\),对角线 \(d=a+b\),则 \(d=s\sqrt2\)。因此, \[ s^2=\frac{d^2}{2}=\frac12(a+b)^2\text{。}\]

因此,正确答案是 B。

English

If \(s\) is the side length and \(d=a+b\) is the diagonal, then \(d=s\sqrt2.\) Thus \[ s^2=\frac{d^2}{2}=\frac12(a+b)^2. \]

Thus, the correct answer is B.

4 答案 D

四面墙单侧的面积为 \[ 2(13\cdot5)+2(10\cdot5)=230\text{。}\]内外两侧共需粉刷 \(2(230)=460\)。天花板再增加 \(10\cdot13=130\),所以总面积为 \(460+130=590\)。

因此,正确答案是 D。

English

The four walls have one-sided area \[ 2(13\cdot5)+2(10\cdot5)=230. \] Painting them inside and outside contributes \(2(230)=460.\) The ceiling adds \(10\cdot13=130,\) so the total is \(460+130=590.\)

Thus, the correct answer is D.

5 答案 B

第一次售价为 \(10{,}000(1.10)=11{,}000\)。卖回时的售价为 \(11{,}000(0.90)=9{,}900\)。\(A\) 先生收到 \(11{,}000\),再付出 \(9{,}900\),所以获利 \(1{,}100\)。

因此,正确答案是 B。

English

The first sale price is \(10{,}000(1.10)=11{,}000.\) The return sale is \(11{,}000(0.90)=9{,}900.\) Mr. \(A\) receives \(11{,}000\) and pays back \(9{,}900,\) so he gains \(1{,}100.\)

Thus, the correct answer is B.

6 答案 D

若三条棱长为 \(l,w,h\),则三个面的面积为 \(lw\)、\(wh\) 和 \(hl\)。它们的乘积为 \[ (lw)(wh)(hl)=l^2w^2h^2=(lwh)^2\text{,}\]即体积的平方。

因此,正确答案是 D。

English

If the edge lengths are \(l,w,h,\) the three face areas are \(lw,\) \(wh,\) and \(hl.\) Their product is \[ (lw)(wh)(hl)=l^2w^2h^2=(lwh)^2, \] the square of the volume.

Thus, the correct answer is D.

7 答案 B

两个相对误差分别为 \(\frac{0.02}{10}=0.002\) 和 \(\frac{0.2}{100}=0.002\)。它们相等。

因此,正确答案是 B。

English

The two relative errors are \(\frac{0.02}{10}=0.002\) and \(\frac{0.2}{100}=0.002.\) They are equal.

Thus, the correct answer is B.

8 答案 C

设原价为 \(1\)。降价后的价格为 \(0.9\)。所需的增幅为 \[ \frac{1-0.9}{0.9}=\frac19\text{,}\]即 \(11\dfrac19\%\)。

因此,正确答案是 C。

English

Let the original price be \(1.\) The reduced price is \(0.9.\) The required fractional increase is \[ \frac{1-0.9}{0.9}=\frac19, \] which is \(11\dfrac19\%.\)

Thus, the correct answer is C.

9 答案 D

第一个三角形的周长为 \(3a\),以后每个周长都是前一个的一半。因此,总和为 \[ \begin{aligned} &3a\left(1+\frac12+\frac14+\cdots\right)\\ &\quad=3a\cdot\frac{1}{1-\frac12}\\ &\quad=6a \end{aligned}\text{。}\]

因此,正确答案是 D。

English

The first perimeter is \(3a,\) and every later perimeter is half the preceding one. Hence the total is \[ \begin{aligned} &3a\left(1+\frac12+\frac14+\cdots\right)\\ &\quad=3a\cdot\frac{1}{1-\frac12}\\ &\quad=6a. \end{aligned} \]

Thus, the correct answer is D.

10 答案 C

圆的面积为 \(\pi r^2\)。将 \(r\) 替换为 \(2r\),得到 \(\pi(2r)^2=4\pi r^2\),所以半径加倍会使面积变为四倍,而不是两倍。其余说法按原文均可成立。

因此,正确答案是 C。

English

A circle has area \(\pi r^2.\) Replacing \(r\) by \(2r\) gives \(\pi(2r)^2=4\pi r^2,\) so doubling the radius quadruples, rather than doubles, the area. The other statements can hold as written.

Thus, the correct answer is C.

11 答案 C

各项平方后仍组成等比数列,首项为 \(a^2\),公比为 \(r^2\)。因为 \(|r|\lt1\),所以其和为 \[ \frac{a^2}{1-r^2}\text{。}\]

因此,正确答案是 C。

English

The squared terms form a geometric series with first term \(a^2\) and ratio \(r^2.\) Since \(|r|\lt1,\) its sum is \[ \frac{a^2}{1-r^2}. \]

Thus, the correct answer is C.

12 答案 C

在 \(2{:}15\) 时,分针与 \(12\) 点方向成 \(90^\circ\) 角。时针与 \(12\) 点方向所成的角为 \(2\cdot30^\circ+15\cdot0.5^\circ=67.5^\circ\)。两针夹角为 \(90^\circ-67.5^\circ=22.5^\circ=22\dfrac12^\circ\)。

因此,正确答案是 C。

English

At \(2{:}15\) the minute hand is \(90^\circ\) from \(12.\) The hour hand is \(2\cdot30^\circ+15\cdot0.5^\circ=67.5^\circ\) from \(12.\) Their angle is \(90^\circ-67.5^\circ=22.5^\circ=22\dfrac12^\circ.\)

Thus, the correct answer is C.

13 答案 C

\(A\) 每天完成全部工作的 \(\frac{1}{9}\)。因此,\(B\) 每天完成的工作量为 \[ \frac32\cdot\frac19=\frac16\text{,}\]所以 \(B\) 需要 \(6\) 天。

因此,正确答案是 C。

English

\(A\)’s rate is \(\frac{1}{9}\) job per day. Thus \(B\)’s rate is \[ \frac32\cdot\frac19=\frac16 \] job per day, so \(B\) needs \(6\) days.

Thus, the correct answer is C.

14 答案 C

公理化体系以有意不加定义的原始术语以及无需证明即可接受的陈述为起点。因此,“证明中的每一个术语都必须事先定义”这一说法不正确。

因此,题目预期的正确答案是 C。

English

An axiomatic development begins with primitive terms that are deliberately left undefined, as well as statements accepted without proof. Therefore it is not true that every term in a proof must previously have been defined.

Thus, the intended correct answer is C.

15 答案 E

有 \[ n^3-n=n(n-1)(n+1)\text{,}\]这是三个连续整数的乘积。其中一个能被 \(3\) 整除,且至少一个是偶数,所以该乘积恒能被 \(6\) 整除。取 \(n=2\) 时,表达式的值恰为 \(6\),所以不存在更大的整数能恒整除该表达式。

因此,正确答案是 E。

English

We have \[ n^3-n=n(n-1)(n+1), \] a product of three consecutive integers. One is divisible by \(3\) and at least one is even, so the product is always divisible by \(6.\) Taking \(n=2\) gives exactly \(6,\) so no larger integer always divides it.

Thus, the correct answer is E.

16 答案 C

由所给条件可得 \[ b^2-4ac=b^2-4a\left(\frac{b^2}{4a}\right)=0\text{。}\]因此,该二次方程有一个二重实根,其抛物线与 \(x\) 轴相切。

因此,正确答案是 C。

English

The condition gives \[ b^2-4ac=b^2-4a\left(\frac{b^2}{4a}\right)=0. \] Hence the quadratic has a repeated real root, so its parabola is tangent to the \(x\)-axis.

Thus, the correct answer is C.

17 答案 D

选项 A、C 和 E 均可整理为 \(y=kx\),选项 B 可整理为 \(xy=k\)。但选项 D 给出 \(y=10-3x\),不属于这两种形式。

因此,正确答案是 D。

English

Choices A, C, and E rearrange to \(y=kx,\) and choice B rearranges to \(xy=k.\) But choice D gives \(y=10-3x,\) which is neither form.

Thus, the correct answer is D.

18 答案 D

设 \[ \begin{aligned} &21x^2+ax+21\\ &\quad=(Ax+B)(Cx+D) \end{aligned}\text{。}\]则 \(AC=BD=21\),所以 \(A,B,C,D\) 均为奇数。因此,\(a=AD+BC\) 为偶数。某些偶数确实可行;例如,\[ \begin{aligned} &(3x+7)(7x+3)\\ &\quad=21x^2+58x+21 \end{aligned}\text{。}\]但并非每个偶数都可行。

因此,正确答案是 D。

English

Suppose \[ \begin{aligned} &21x^2+ax+21\\ &\quad=(Ax+B)(Cx+D). \end{aligned} \] Then \(AC=BD=21,\) so \(A,B,C,D\) are odd. Therefore \(a=AD+BC\) is even. Some even values work; for example, \[ \begin{aligned} &(3x+7)(7x+3)\\ &\quad=21x^2+58x+21. \end{aligned} \] Not every even value works.

Thus, the correct answer is D.

19 答案 E

若被重复的三位数为 \(N\),则这个六位数为 \[ 1000N+N=1001N\text{。}\]因此,它一定能被 \(1001\) 整除。

因此,正确答案是 E。

English

If the repeated block is \(N,\) then the six-place number is \[ 1000N+N=1001N. \] It is therefore always divisible by \(1001.\)

Thus, the correct answer is E.

20 答案 C

当 \(x,y\) 均不为零且 \(x+y\ne0\) 时,\[ \begin{aligned} &(x+y)^{-1}(x^{-1}+y^{-1})\\ &\quad=\frac{1}{x+y}\left(\frac{x+y}{xy}\right)\\ &\quad=\frac1{xy}=x^{-1}y^{-1} \end{aligned}\text{。}\]

因此,正确答案是 C。

English

For nonzero \(x,y\) with \(x+y\ne0,\) \[ \begin{aligned} &(x+y)^{-1}(x^{-1}+y^{-1})\\ &\quad=\frac{1}{x+y}\left(\frac{x+y}{xy}\right)\\ &\quad=\frac1{xy}=x^{-1}y^{-1}. \end{aligned} \]

Thus, the correct answer is C.

21 答案 C

因为 \(z\) 可能为负数,所以将 \(x\gt y\) 两边乘以 \(z\) 会使不等号反向,得到 \(xz\lt yz\)。其他选项中的运算都保持不等式成立,因为 \(z^2\gt0\)。

因此,正确答案是 C。

English

Because \(z\) may be negative, multiplying \(x\gt y\) by \(z\) reverses the inequality and gives \(xz\lt yz.\) The operations in the other choices preserve the inequality because \(z^2\gt0.\)

Thus, the correct answer is C.

22 答案 B

原方程等价于 \(a^2-15a=10^2=100\),所以 \[ \begin{aligned} &a^2-15a-100\\ &\quad=(a-20)(a+5)\\ &\quad=0 \end{aligned}\text{。}\]\(a=20\) 与 \(a=-5\) 都使对数的真数等于 \(100\),因此两个解都有效。

因此,正确答案是 B。

English

The equation is equivalent to \(a^2-15a=10^2=100,\) so \[ \begin{aligned} &a^2-15a-100\\ &\quad=(a-20)(a+5)\\ &\quad=0. \end{aligned} \] Both \(a=20\) and \(a=-5\) make the logarithm’s argument \(100,\) so both are valid.

Thus, the correct answer is B.

23 答案 B

要使两种新体积相等,必须有 \[ 3\pi(8+x)^2=64\pi(3+x)\text{。}\]约去 \(\pi\) 并展开,得到 \(3x^2-16x=0\),所以 \(x=0\) 或 \(x=\frac{16}{3}=5\dfrac13\)。题目要求增量非零。

因此,正确答案是 B。

English

For the two new volumes to be equal, \[ 3\pi(8+x)^2=64\pi(3+x). \] Cancelling \(\pi\) and expanding gives \(3x^2-16x=0,\) so \(x=0\) or \(x=\frac{16}{3}=5\dfrac13.\) The problem requires a nonzero increase.

Thus, the correct answer is B.

24 答案 D

因式分解并合并幂,得到 \[ \frac{2^n(2^4-2)}{2^{n+4}} =\frac{14}{16} =\frac78\text{。}\]

因此,正确答案是 D。

English

Factoring and combining powers gives \[ \frac{2^n(2^4-2)}{2^{n+4}} =\frac{14}{16} =\frac78. \]

Thus, the correct answer is D.

25 答案 A

边心距为 \(r\)、周长为 \(P\) 的任意正多边形,其面积为 \(A=\frac12rP\)。若面积数值等于非零的周长数值,则 \[ \frac12rP=P\text{,}\]所以 \(r=2\)。正方形与等边三角形都满足这一结论,因此二者的边心距相等。

因此,正确答案是 A。

English

Every regular polygon with apothem \(r\) and perimeter \(P\) has area \(A=\frac12rP.\) If its numerical area equals its nonzero perimeter, then \[ \frac12rP=P, \] so \(r=2.\) This applies to both the square and the equilateral triangle, so their apothems are equal.

Thus, the correct answer is A.

26 答案 E

消去分母并化简,得到 \[ x^2-x-m(m+1)=0\text{。}\]两根相等要求 \[ \begin{aligned} 1+4m(m+1) &=(2m+1)^2\\ &=0 \end{aligned}\text{,}\]因此 \(m=-\frac12\)。该值不会使原方程的分母为零。

因此,正确答案是 E。

English

Clearing denominators and simplifying yields \[ x^2-x-m(m+1)=0. \] Equal roots require \[ \begin{aligned} 1+4m(m+1) &=(2m+1)^2\\ &=0, \end{aligned} \] hence \(m=-\frac12.\) This value does not violate the original denominators.

Thus, the correct answer is E.

27 答案 E

题目没有给出任何角度或长度条件,足以保证相对区域相似或全等。它们的面积也不必相等:将内点放在非常靠近某一边的位置,可使邻接该边的区域任意小,却不会迫使其相对区域也变小。六个区域中也没有四边形。

因此,正确答案是 E。

English

No angle or length condition forces opposite sections to be similar or congruent. Their areas also need not match: placing the interior point very close to one side makes the sections adjoining that side arbitrarily small without forcing their opposite sections to be small. No quadrilaterals are among the six sections.

Thus, the correct answer is E.

28 答案 C

写成 \(P=kAV^2\)。由 \(1=k(1)(16^2)\) 得 \(k=\frac{1}{256}\)。一平方码等于 \(9\) 平方英尺,所以 \[ 36=\frac1{256}\cdot9V^2\text{。}\]因此 \(V^2=1024\),正的风速为 \(V=32\) 英里/小时。

因此,正确答案是 C。

English

Write \(P=kAV^2.\) From \(1=k(1)(16^2),\) we get \(k=\frac{1}{256}.\) A square yard has area \(9\) square feet, so \[ 36=\frac1{256}\cdot9V^2. \] Thus \(V^2=1024\) and the positive speed is \(V=32\) mph.

Thus, the correct answer is C.

29 答案 D

选项 A 和 E 可在相似意义下确定各角。三条高之比确定相应边长的倒数之比,三条中线之比也能确定边长之比。但仅有一个比值 \(\frac{h}{b}\),无法确定其余边长或角;许多不相似的三角形都可以具有这一比值。

因此,正确答案是 D。

English

Choices A and E determine the angles up to similarity. Ratios of all three altitudes determine reciprocal side ratios, and ratios of all three medians determine side ratios. But a single ratio \(\frac{h}{b}\) does not determine the remaining side lengths or angles; many non-similar triangles can share it.

Thus, the correct answer is D.

30 答案 C

将两根杆的底端置于 \((0,0)\) 和 \((100,0)\),顶端分别为 \((0,80)\) 和 \((100,20)\)。两条交叉连线为 \(y=\frac45x\) 和 \(y=20-\frac15x\)。令二者相等,得到 \(x=20\),进而得到 \(y=16\)。

因此,正确答案是 C。

English

Put the bases at \((0,0)\) and \((100,0),\) with tops \((0,80)\) and \((100,20).\) The cross-lines are \(y=\frac45x\) and \(y=20-\frac15x.\) Equating them gives \(x=20,\) and hence \(y=16.\)

Thus, the correct answer is C.

31 答案 D

若有 \(n\) 人,则握手次数为 \[ \binom n2=\frac{n(n-1)}2\text{。}\]因此 \(n(n-1)=56\),正解为 \(n=8\)。

因此,正确答案是 D。

English

With \(n\) people the number of handshakes is \[ \binom n2=\frac{n(n-1)}2. \] Thus \(n(n-1)=56,\) and the positive solution is \(n=8.\)

Thus, the correct answer is D.

32 答案 D

由泰勒斯定理,\(AC\) 和 \(BC\) 是以 \(AB\) 为斜边的直角三角形的两条直角边。因此 \[ \begin{aligned} (AC+BC)^2 &\le2(AC^2+BC^2)\\ &=2AB^2 \end{aligned}\text{。}\]两边取正平方根,得到 \(AC+BC\le AB\sqrt2\);当三角形为等腰直角三角形时取等号。

因此,正确答案是 D。

English

By Thales’ theorem, \(AC\) and \(BC\) are the legs of a right triangle with hypotenuse \(AB.\) Therefore \[ \begin{aligned} (AC+BC)^2 &\le2(AC^2+BC^2)\\ &=2AB^2. \end{aligned} \] Taking positive square roots gives \(AC+BC\le AB\sqrt2,\) with equality for an isosceles right triangle.

Thus, the correct answer is D.

33 答案 C

选项 A、B、D 和 E 的交点条件均可化为 \(x^2-2x=0\)。选项 C 却要求 \[ x=x-2\text{,}\]该方程无解,因此不能给出所求的根。

因此,正确答案是 C。

English

Choices A, B, D, and E all reduce their intersection condition to \(x^2-2x=0.\) Choice C instead requires \[ x=x-2, \] which has no solution and therefore cannot produce the desired roots.

Thus, the correct answer is C.

34 答案 A

因为以 \(10\) 为底的指数函数与对数函数互为反函数,所以 \[ 10^{\log_{10}7}=7\text{。}\]

因此,正确答案是 A。

English

Since the base-\(10\) exponential and logarithm are inverse functions, \[ 10^{\log_{10}7}=7. \]

Thus, the correct answer is A.

35 答案 A

取对数,得到 \[ \begin{gathered} x\log a=q\log c,\\ y\log c=z\log a \end{gathered}\text{。}\]按照本题历史上对非退化底数的约定,将两式相乘并约去非零的对数因子,得到 \(xy=qz\)。

因此,题目预期的正确答案是 A。

English

Taking logarithms gives \[ \begin{gathered} x\log a=q\log c,\\ y\log c=z\log a. \end{gathered} \] Multiplying these equations and cancelling the nonzero logarithmic factors under the historical nondegenerate-base convention yields \(xy=qz.\)

Thus, the intended correct answer is A.

36 答案 B

令 \(L\) 表示“在轨迹上”,\(C\) 表示“满足条件”。完整的证明需要同时证明 \(L\Rightarrow C\) 和 \(C\Rightarrow L\)。选项 B 先陈述 \(\neg C\Rightarrow\neg L\),这只是 \(L\Rightarrow C\) 的逆否命题,随后又重复 \(L\Rightarrow C\)。它始终没有证明 \(C\Rightarrow L\)。

因此,正确答案是 B。

English

Let \(L\) mean “on the locus” and \(C\) mean “satisfies the conditions.” A complete proof needs both \(L\Rightarrow C\) and \(C\Rightarrow L.\) Choice B states \(\neg C\Rightarrow\neg L,\) which is merely the contrapositive of \(L\Rightarrow C,\) and then repeats \(L\Rightarrow C.\) It never proves \(C\Rightarrow L.\)

Thus, the correct answer is B.

37 答案 D

若这个数为 \(N\),则 \(N+1\) 能被从 \(2\) 到 \(10\) 的每个整数整除。这些整数的最小公倍数为 \[ 2^3\cdot3^2\cdot5\cdot7=2520\text{。}\]因此,满足所有条件的最小正数为 \(N=2520-1=2519\)。

因此,正确答案是 D。

English

If the number is \(N,\) then \(N+1\) is divisible by every integer from \(2\) through \(10.\) Their least common multiple is \[ 2^3\cdot3^2\cdot5\cdot7=2520. \] Thus the least positive number fitting all the conditions is \(N=2520-1=2519.\)

Thus, the correct answer is D.

38 答案 A

\(3\%\) 的坡度需要约 \(\frac{600}{0.03}=20{,}000\) 英尺长的轨道,而 \(2\%\) 的坡度需要 \(\frac{600}{0.02}=30{,}000\) 英尺。需要增加的长度为 \(10{,}000\) 英尺。

因此,正确答案是 A。

English

A \(3\%\) grade requires about \(\frac{600}{0.03}=20{,}000\) feet of track, while a \(2\%\) grade requires \(\frac{600}{0.02}=30{,}000\) feet. The additional length is \(10{,}000\) feet.

Thus, the correct answer is A.

39 答案 A

若石头下落 \(t\) 秒,则井深为 \(16t^2\),声音传回井口所需的时间为 \(\frac{16t^2}{1120}=\frac{t^2}{70}\) 秒。因此 \[ t+\frac{t^2}{70}=7.7\text{,}\]即 \(t^2+70t-539=0\)。正根为 \(t=7\),故井深为 \(16(7^2)=784\) 英尺。

因此,正确答案是 A。

English

If the stone falls for \(t\) seconds, the depth is \(16t^2,\) and the sound takes \(\frac{16t^2}{1120}=\frac{t^2}{70}\) seconds to return. Hence \[ t+\frac{t^2}{70}=7.7, \] or \(t^2+70t-539=0.\) The positive root is \(t=7,\) giving depth \(16(7^2)=784\) feet.

Thus, the correct answer is A.

40 答案 C

因为 \[ \begin{aligned} x^3+1&=(x+1)(x^2-x+1),\\ x^3-1&=(x-1)(x^2+x+1) \end{aligned}\text{,}\]所以在原表达式有定义时,括号内的每个分式都等于 \(1\)。因此,二者平方后的乘积为 \(1\)。

因此,正确答案是 C。

English

Because \[ \begin{aligned} x^3+1&=(x+1)(x^2-x+1),\\ x^3-1&=(x-1)(x^2+x+1), \end{aligned} \] each fraction inside parentheses equals \(1\) wherever the original expression is defined. Their squared product is therefore \(1.\)

Thus, the correct answer is C.

41 答案 B

这些 \(y\) 值可以自然地写成 \[ \begin{gathered} 0=1\cdot0,\quad 2=2\cdot1,\quad 6=3\cdot2,\\ 12=4\cdot3,\quad 20=5\cdot4 \end{gathered}\text{。}\]因此 \(y=(x-1)(x-2)\),从而 \(y=x^2-3x+2\)。

因此,正确答案是 B。

English

The \(y\)-values factor naturally as \[ \begin{gathered} 0=1\cdot0,\quad 2=2\cdot1,\quad 6=3\cdot2,\\ 12=4\cdot3,\quad 20=5\cdot4. \end{gathered} \] Thus \(y=(x-1)(x-2)\) and hence \(y=x^2-3x+2.\)

Thus, the correct answer is B.

42 答案 C

由无限重复的尾部可得 \(x=\sqrt{1+x}\),所以 \[ x^2-x-1=0\text{。}\]因为 \(x\ge0\),所以 \(x=\frac{1+\sqrt5}{2}\),该值严格位于 \(1\) 与 \(2\) 之间。

因此,正确答案是 C。

English

The repeating tail gives \(x=\sqrt{1+x},\) so \[ x^2-x-1=0. \] Since \(x\ge0,\) \(x=\frac{1+\sqrt5}{2},\) which lies strictly between \(1\) and \(2.\)

Thus, the correct answer is C.

43 答案 E

若 \(uv=P\gt0\),则 \(u+v\ge2\sqrt P\),并在 \(u=v\) 时取等号。因此,两数相等时得到的是最小的和。令 \(u\) 任意增大,同时令 \(v=\frac{P}{u}\) 变小,二者之和可以无限增大,所以两数相等时和并非最大。

因此,正确答案是 E。

English

If \(uv=P\gt0,\) then \(u+v\ge2\sqrt P,\) with equality at \(u=v.\) Thus equality gives the least possible sum. The sum can grow without bound by taking \(u\) large and \(v=\frac{P}{u}\) small, so it is not greatest at equality.

Thus, the correct answer is E.

44 答案 E

分别取倒数,得到 \[ \begin{gathered} \frac1x+\frac1y=\frac1a,\\ \frac1x+\frac1z=\frac1b,\\ \frac1y+\frac1z=\frac1c \end{gathered}\text{。}\]将前两式相加,再减去第三式,得到 \[ \begin{aligned} \frac2x &=\frac1a+\frac1b-\frac1c\\ &=\frac{ac+bc-ab}{abc} \end{aligned}\text{。}\]因此 \(x=\dfrac{2abc}{ac+bc-ab}\)。

因此,正确答案是 E。

English

Inverting gives \[ \begin{gathered} \frac1x+\frac1y=\frac1a,\\ \frac1x+\frac1z=\frac1b,\\ \frac1y+\frac1z=\frac1c. \end{gathered} \] Adding the first two and subtracting the third yields \[ \begin{aligned} \frac2x &=\frac1a+\frac1b-\frac1c\\ &=\frac{ac+bc-ab}{abc}. \end{aligned} \] Hence \(x=\dfrac{2abc}{ac+bc-ab}.\)

Thus, the correct answer is E.

45 答案 A

由已知条件,\[ \begin{gathered} \log2=\frac13\log8,\\ \log3=\frac12\log9 \end{gathered}\text{,}\]并且 \(\log5=1-\log2\)。因此,可以求出由 \(2,3,5\) 的幂相乘或相除所得各数的对数。\(17\) 不含这些质因数中的任何一个,所以仅凭已知条件不能确定其对数。

因此,正确答案是 A。

English

From the data, \[ \begin{gathered} \log2=\frac13\log8,\\ \log3=\frac12\log9, \end{gathered} \] and \(\log5=1-\log2.\) Therefore logarithms of products and quotients of powers of \(2,3,5\) can be computed. The number \(17\) has none of those prime factors, so its logarithm is not determined by the data.

Thus, the correct answer is A.

46 答案 A

延长 \(CO\),使其再次交圆于 \(E\)。因为 \(CE\) 是直径,所以 \(\angle CDE=90^\circ\)。又因为 \(CD\perp AB\),所以 \(DE\parallel AB\)。若 \(\angle OCD=\angle ECD\) 的平分线交圆于 \(P\),则相等的圆周角所对弧相等,故 \(EP=PD\)。由于平行弦 \(DE\) 的两个端点关于固定直径 \(AB\) 对称分布,其弧中点 \(P\) 就是弧 \(AB\) 的中点。

因此,正确答案是 A。

English

Extend \(CO\) to meet the circle again at \(E.\) Since \(CE\) is a diameter, \(\angle CDE=90^\circ.\) Also \(CD\perp AB,\) so \(DE\parallel AB.\) If the bisector of \(\angle OCD=\angle ECD\) meets the circle at \(P,\) equal inscribed angles give equal arcs \(EP=PD.\) Because the parallel chord \(DE\) has endpoints symmetrically placed relative to the fixed diameter \(AB,\) their arc midpoint \(P\) is the midpoint of arc \(AB.\)

Thus, the correct answer is A.

47 答案 D

由韦达定理,\[ r+s=-\frac ba,\qquad rs=\frac ca\text{。}\]因此 \[ \begin{aligned} \frac1{r^2}+\frac1{s^2} &=\frac{(r+s)^2-2rs}{(rs)^2}\\ &=\frac{b^2-2ac}{c^2} \end{aligned}\text{。}\]

因此,正确答案是 D。

English

By Vieta’s formulas, \[ r+s=-\frac ba,\qquad rs=\frac ca. \] Therefore \[ \begin{aligned} \frac1{r^2}+\frac1{s^2} &=\frac{(r+s)^2-2rs}{(rs)^2}\\ &=\frac{b^2-2ac}{c^2}. \end{aligned} \]

Thus, the correct answer is D.

48 答案 C

对于内接于半圆的正方形,将其底边放在直径上。一个上顶点到圆心的水平距离为 \(\frac{s}{2}\),竖直距离为 \(s\),所以 \[ \left(\frac s2\right)^2+s^2=R^2\text{,}\]得到 \(s^2=\frac{4R^2}{5}\)。内接于整圆的正方形对角线长为 \(2R\),故面积为 \(2R^2\)。所求比为 \[ \frac{\frac{4R^2}{5}}{2R^2}=\frac25\text{。}\]

因此,正确答案是 C。

English

For the square in the semicircle, put its base on the diameter. A top vertex has horizontal distance \(\frac{s}{2}\) from the center and vertical distance \(s,\) so \[ \left(\frac s2\right)^2+s^2=R^2, \] giving \(s^2=\frac{4R^2}{5}.\) A square inscribed in the full circle has diagonal \(2R,\) hence area \(2R^2.\) The ratio is \[ \frac{\frac{4R^2}{5}}{2R^2}=\frac25. \]

Thus, the correct answer is C.

49 答案 D

设两条直角边为 \(a,b\)。从其相对的锐角顶点所作中线的长度平方满足 \[ a^2+\frac{b^2}{4}=25,\qquad \frac{a^2}{4}+b^2=40\text{。}\]解得 \(a^2=16\) 和 \(b^2=36\)。因此,斜边 \(c\) 满足 \[ c^2=a^2+b^2=52\text{,}\]所以 \(c=2\sqrt{13}\)。

因此,正确答案是 D。

English

Let the legs be \(a,b.\) The medians from their opposite acute vertices have squared lengths \[ a^2+\frac{b^2}{4}=25,\qquad \frac{a^2}{4}+b^2=40. \] Solving gives \(a^2=16\) and \(b^2=36.\) Thus the hypotenuse \(c\) satisfies \[ c^2=a^2+b^2=52, \] so \(c=2\sqrt{13}.\)

Thus, the correct answer is D.

50 答案 D

令 \(t_1,t_2,t_3\) 分别为哈里下车前汽车行驶的时间、汽车返回接迪克的时间以及汽车载着迪克向前行驶的时间。汽车、迪克和哈里各自行进 \(100\) 英里,因此 \[ \begin{aligned} 25t_1-25t_2+25t_3&=100,\\ 5t_1+5t_2+25t_3&=100,\\ 25t_1+5t_2+5t_3&=100 \end{aligned}\text{。}\]各式除以 \(5\) 并求解,得到 \(t_1=3,\ t_2=2,\ t_3=3\)。因此,他们共同的行程时间为 \(t_1+t_2+t_3=8\) 小时。

因此,正确答案是 D。

English

Let \(t_1,t_2,t_3\) be the car’s times before Harry leaves it, while it returns for Dick, and while it carries Dick forward. The car, Dick, and Harry each cover \(100\) miles, giving \[ \begin{aligned} 25t_1-25t_2+25t_3&=100,\\ 5t_1+5t_2+25t_3&=100,\\ 25t_1+5t_2+5t_3&=100. \end{aligned} \] Dividing by \(5\) and solving yields \(t_1=3,\ t_2=2,\ t_3=3.\) Therefore the common travel time is \(t_1+t_2+t_3=8\) hours.

Thus, the correct answer is D.

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